64m^2-810=0

Solution for 64m^2-810=0 equation:

64m^2-810=0

a = 64; b = 0; c = -810;
Δ = b2-4ac
Δ = 02-4·64·(-810)
Δ = 207360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{207360}=\sqrt{20736*10}=\sqrt{20736}*\sqrt{10}=144\sqrt{10}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-144\sqrt{10}}{2*64}=\frac{0-144\sqrt{10}}{128}
=-\frac{144\sqrt{10}}{128}
=-\frac{9\sqrt{10}}{8}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+144\sqrt{10}}{2*64}=\frac{0+144\sqrt{10}}{128}
=\frac{144\sqrt{10}}{128}
=\frac{9\sqrt{10}}{8}
$